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ATQ Quantity of milk in 520 ml of mixture = 520 × 10/(10 + z) Quantity of water in 520 ml of mixture = 520 × z/(z + 10) According to the question: {5200/(10 + z) + 90}/{520z/(z + 10) + 80} = 4/1 Or, 5200/(10 + z) + 90 = 2080z/(z + 10) + 320 Or, (5200 – 2080z)/(z + 10) = 230 Or, 5200 – 2080z = 230z + 2300 Or, 2310z = 2900 Or, z = 2
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