A container holds a mixture of alcohol and water in the ratio 4:7, respectively. 25 liters of the mixture is drawn out and replaced with the same quantity of alcohol. The process is repeated once more. If the ratio of water to alcohol in the mixture is now 121:167, find the capacity of the container. (Assume the container is full)
ATQ,
Let the container's capacity be C liters. Initially, alcohol and water are in the ratio 4:7. After 25 liters of the mixture is drawn out and replaced with alcohol twice, the final ratio of water to alcohol becomes 121:167. Set up the equation for water remaining after two replacements: 
Solving this equation gives C = 275 liters.
The capacity of the container is 275 liters.
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