A container holds a mixture of two liquids, A and B, in the ratio 2:3. If the total volume of the mixture is 70 liters, how many liters of liquid A must be added to make the ratio of A to B equal to 3:2?
Current volumes: A = (2/5) * 70 = 28 liters; B = (3/5) * 70 = 42 liters. Let x be the amount of A to be added. (28 + x) / 42 = 3/2 Cross-multiplying: 2(28 + x) = 3 * 42 56 + 2x = 126 2x = 70 → x = 35 liters
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