Question
A container holds a mixture of two liquids, A and B, in
the ratio 2:3. If the total volume of the mixture is 70 liters, how many liters of liquid A must be added to make the ratio of A to B equal to 3:2?Solution
Current volumes: A = (2/5) * 70 = 28 liters; B = (3/5) * 70 = 42 liters. Let x be the amount of A to be added. (28 + x) / 42 = 3/2 Cross-multiplying: 2(28 + x) = 3 * 42 56 + 2x = 126 2x = 70 → x = 35 liters
2 (1/4)% of 7999.58 + {49.06% of 898.87} + √143.14 – 19.99% of 1499.63 - (52 - 41) = ?
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 499.87 – 24.95 × 14.04 + (20.15)²
( 22.01%  of 899.80 ) × 15.99 = ? 2 + 27.98 × 2400 ÷ 800
(1331)1/3 x 10.11 x 7.97 ÷ 16.32 =? + 15.022
24.912% of ? – 35.06% of 199.91 = 19.97% of 224.89
(2220.23 ÷ 36.98) + (768.32 ÷ 23.9) + 1644.11 = ?
What will be the approximate value of the following questions.
(1/2 of 959.90 + 69.69% of 359.79) ÷ (√63.94 × 2/5 of 250.14) = ?
40.93√? + √6625 + √6920 + √? = 205.7542`xx` 7.654
[{(√785) % of 449.85}/(35.89 × 7.14 + 849.89 ÷ 5.12 + 199.78% of 41.09)] = ( 1/? )Â
