Question
A 456 ml mixture consists of milk and water in a 12:7
ratio. If 'x + 22' ml of milk and 'x - 18' ml of water are added, the new ratio of milk to water becomes 9:5. Determine the value of 'x'.Solution
Quantity of milk in 456 ml of mixture = (12/19) × 456 = 288 ml Quantity of water in 456 ml of mixture = 456 – 288 = 168 ml So, {(288 + x + 22)/(168 + x – 18)} = 9/5 Or, 1550 + 5x = 1350 + 9x Or, 4x = 200 Or, x = 50 Hence, option b
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