A mixture contains alcohol and water in the ratio of 3:2. If 15 liters of water is added to the mixture, the ratio becomes 3:5. Find the initial quantity of alcohol in the mixture.
Let the initial quantities of alcohol and water be 3x and 2x liters, respectively. When 15 liters of water is added, the new ratio becomes 3:5: (3x) / (2x + 15) = 3/5 Cross-multiply: 5 × 3x = 3 × (2x + 15) 15x = 6x + 45 9x = 45 x = 5 Initial alcohol = 3x = 15 liters Correct answer: d) 15 liters
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