Question
A mixture contains alcohol and water in the ratio of
3:2. If 15 liters of water is added to the mixture, the ratio becomes 3:5. Find the initial quantity of alcohol in the mixture.Solution
Let the initial quantities of alcohol and water be 3x and 2x liters, respectively. When 15 liters of water is added, the new ratio becomes 3:5: (3x) / (2x + 15) = 3/5 Cross-multiply: 5 × 3x = 3 × (2x + 15) 15x = 6x + 45 9x = 45 x = 5 Initial alcohol = 3x = 15 liters Correct answer: d) 15 liters
38, 41, 50, ?, 158, 401Â
15.975 ×27.825 + (76.01)² + 12.98×18.426 = ?+ (79.09)²
Find the missing term in the series:
2, 7, 22, 67, 202, ?
13    13      26       ?      832       13312
...100, 120, 260, ?, 3220, 16120
0, 6, 24, ?, 120, 210
What will come in place of the question mark (?) in the following series?
50, 70, 110, 190, 310, ?
8      27       64      125     ?       343Â
...- What will come in place of (?) in the given number series.
3, 9, 15, 21, ?, 33 What value should come in the place of (?) in the following number series?
?, 664, 706, 769, 853, 958
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