In a solution, 35% of the water's quantity is chlorine. After extracting 81 liters of this solution and adding 15 liters of chlorine and 15 liters of water, the chlorine's volume in the new mixture is 26 liters less than the water. Determine the amount of water in this adjusted mixture.
After removal of 81 litres of mixture, Let the initial quantity of water be '100a' litres. Initial quantity of chlorine = 0.35 X 100a = '35a' litres ATQ, 100a - 35a = 26 Or, 65a = 26 Or, 'a' = (26/65) = 0.4 Therefore, final quantity of water = 100a + 15 = 100 X 0.4 + 15 = 40 + 15 = 55 litres
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