A container holds 'x' liters of a mixture composed of liquids A and B in a 5:2 ratio. If 25% of this mixture is removed and then 6 liters of liquid B are added, the new quantity of liquid B becomes 15 liters. Determine the original volume 'x' of the mixture.
Quantity of liquid A initially = 5x/7 litres Quantity of liquid B initially = 2x/7 litres According to question, 0.75 × (2x/7) + 6 = 15 0.75 × (2x/7) = 9 2x/7 = 12, x = 42 litres
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