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    Question

    A mixture containing 120 liters of milk and water has

    35% of its volume as water. If 24 liters of pure water are added to this mixture, the difference in volume between the milk and water becomes 'P' liters. Calculate 'P'% of the total milk volume in the mixture.
    A 8.24 litres Correct Answer Incorrect Answer
    B 10.92 litres Correct Answer Incorrect Answer
    C 9.36 litres Correct Answer Incorrect Answer
    D 8.96 litres Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Quantity of water in 120 litres mixture = 0.35 X 120 = 42 litres Quantity of milk in 120 litres mixture = 120 - 42 = 78 litres Quantity of water in final mixture = 42 + 24 = 66 litres Difference between quantities of milk and water = 78 - 66 = 12 litres So, 'P' = 12 Therefore, required value = 0.12 X 78 = 9.36 litres

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