Question
A 200-litre mixture of milk and
water is currently in the ratio 3:5. To reduce the percentage of milk in the mixture to 25%, how much additional water must be added?Solution
ATQ, Present (original) quantity of milk in the mixture = 200 × (3/8) = 75 litres So, new quantity of mixture = 75 ÷ 0.25 = 300 litres So, quantity of water to be added = 300 - 200 = 100 litres
24.01 X 24.99 - ?% of 599.96 = 14.92 X 8.12
? = 65.78² ÷ (5.01⁵ + 7.02 × 33.33) + 33.33% of (290.88 × 23.09)
29.88% of 3599.90 + 5/12 of 2399.81 – 34.81% of 1200.18 = ?
999.99 + 99.99 + 99 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
7.898 × ? + 139.89` ` `-:` 14.23 = 4004.04 – 353.89
` `
185.92 ÷ 5.98 - (4.002)2 + 114.03 of 5.03 ÷ 18.99 of 6.04 = 5.01 of 2.99 + ? ÷ 12.02
Monthly income of A is Rs. 66000 out of which he spent 18%, 11% and 21% of his total income in rent, medicine and transportation, respectively. Find his...
? = 650.24 + 1124.97 – 14.992
√784 × 3 + (713.99 ÷ 6.98) = ?% of 619.99
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