Question
A mixture consisting of 40 liters of milk and water has
water accounting for 10% of its total volume. To increase the percentage of water in the mixture to 20%, how many liters of water need to be added?Solution
Initial amount of milk = 36 liters. We need the final solution to have 20% water. Let x liters of water be added. Final solution volume = (40 + x) liters. Milk will remain the same in both the solutions. 80% of (40+x) = 36 0.8×(40+x) = 36 32+0.8x = 36 0.8x = 4 x = 5
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