New 55% Off on All Courses - Enroll Now! Click Here

    Question

    A milkman initially prepared a mixture of milk and water

    in the ratio of 11:3. Later, he replaced half of the mixture with 30 liters of water, resulting in a new mixture where the milk content became 55%. Determine the original total quantity of the mixture.
    A 140 litres Correct Answer Incorrect Answer
    B 161 litres Correct Answer Incorrect Answer
    C 126 litres Correct Answer Incorrect Answer
    D 210 litres Correct Answer Incorrect Answer

    Solution

    Let the original quantity of milk and water in the mixture be '11x' litres and '3x' litres, respectively After replacing half the mixture with 30 litres of water, Quantity of milk remaining in the mixture = 11x ÷ 2 = '5.5x' litres Quantity of water remaining in the mixture = 3x ÷ 2 + 30 = (1.5x + 30) litres According to the question, 5.5x/(1.5x + 30 + 5.5x) = 55/100 Or, 550x = 385x + 1650 So, 165x = 1650 So, x = 1650 ÷ 165 = 10 So, original quantity of the mixture = 11x + 3x = 14x = 14 X 10 = 140 litres

    Practice Next

    Relevant for Exams: