Question
Vessel A contains a mixture of milk and water, with 30
liters of milk. Vessel B also contains a milk-water mixture in the ratio of 5:4. The combined quantity of mixtures in vessels A and B is 140 liters, and the amount of water in vessel B is twice that in vessel A. Determine the quantity of mixture in vessel A.Solution
Milk in vessel A = 30 liters A + B = 140 liters Water in vessel B = 4x Milk in vessel B = 5x Water in vessel A = 4x/2 = 2x 30 + 2x + 4x + 5x = 140 11x = 110 x = 10 Water in vessel A = 2 * 10 = 20 liters Total quantity in vessel A = 20 + 30 = 50 liters Hence answer is option A
If 'a' = √1024 ÷ 4 + 96 ÷ 3 + 85 ÷ 17 and 'b' = 30 × 18 ÷ 6 - 7² + 110, then find the value of (a + b).
... (1782 ÷ 11.98) ÷ 2.92 × 35.89 + 25% of 541 – 67% of 1299 = ?
(2520.33 ÷ 41.67) × (√168.88 + √80.78) - 10% of 1499.85 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
15.232 + 19.98% of 539.99 = ? × 8.99
99% of 4444 + 101% of 6666 =
47.78% of 499.98 + (19.89 × 7.76) = √? × 49.84
The ratio of cost price to the marked price of an article is 5:8. The article had been marked above its cost price by Rs. 270. If the article was sold a...
Find the approximate value of Question mark(?). No need to find the exact value.
(575.86 ÷ 24.03) × (35.96 ÷ 6.03) + √(255.76) = ?
...784.69 + 86.96 ÷ 29.01 = 40.01 + ? + 367.88
