In a mixture of milk and water, the amount of milk is 37

Solution

ATQ, Let the quantity of water in the initial mixture be '4m' ml So, quantity of milk in the initial mixture = (4m + 37) ml Quantity of water after removing 75% mixture = 4m × 0.25 = 'm' ml So, quantity of milk after removing 75% mixture = (4m + 37) × 0.25 = (m + 9.25) ml Quantity of milk after adding 10.75 ml of milk = (m + 9.25 + 10.75) = (m + 20) ATQ. (m + 20) ÷ m = (140/100) Or, 5 × (m + 20) = 7m Or, 100 = (7m - 5m) Or, 2m = 100 So, 'm' = 50 Therefore, initial quantity of mixture = (4m + 4m + 37) = (8m + 37) ml = (8 × 50 + 37) = 437 ml