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ATQ, Let the quantity of water in the initial mixture be '4m' ml So, quantity of milk in the initial mixture = (4m + 37) ml Quantity of water after removing 75% mixture = 4m × 0.25 = 'm' ml So, quantity of milk after removing 75% mixture = (4m + 37) × 0.25 = (m + 9.25) ml Quantity of milk after adding 10.75 ml of milk = (m + 9.25 + 10.75) = (m + 20) ATQ. (m + 20) ÷ m = (140/100) Or, 5 × (m + 20) = 7m Or, 100 = (7m - 5m) Or, 2m = 100 So, 'm' = 50 Therefore, initial quantity of mixture = (4m + 4m + 37) = (8m + 37) ml = (8 × 50 + 37) = 437 ml
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