Start learning 50% faster. Sign in now
Let the quantity of juice and milk after taking out 33 ml of mixture be 6x ml and 5x ml respectively. So, quantity of milk after adding 20 ml milk = (5x + 20) ml ATQ, 6x:(5x + 20) = 6:7 Or, 5x + 20 = 7x So, 2x = 20 Or, x = 10 So, quantity of mixture after taking out 33 ml of mixture = 6x + 5x = 11x = 110 ml Initial quantity of mixture = 110 + 33 = 143 ml So, initial quantity of Juice = 143 X (6/11) = 78 ml
If x = √7 + √6 and y = √7 - √6 , then the value of is (x2 + y2)/(x3 + y3).
...If (x + y + z) = 68, (x/z) = (3/4) and (z/y) = (2/5), then find the value of ‘y’.
(123×123×123 + 130×130×130)/(123×123 - 123×130 + 130×130) = ?
If (x2 + y2 + z2 - 4x + 6y + 13) = 0, then find the value of (x + y + z).
(288 ÷ 8)² × (144 ÷ 24)³ = 24 × ? × (51840 ÷ 20)
If (a3+1)/(a+1) = (a3-1)/(a-1) and a ≠ 1, -1. Find the value of 'a'
What is the highest common factor of (x³ - x² - x - 15) and (x³ - 3x² - 3x + 9)?
If (a + b) = 7 and ab = 9, then find the value of (a2 + b2).