Question
A mixture of milk and water weighs 96 liters, where the
quantity of milk is 33⅓% of the quantity of water. How much milk needs to be added so that the quantity of water in the new mixture becomes 40% of the total volume of the resulting mixture?Solution
Let initial quantity of water be '3y' litres. Initial quantity of milk = (1/3) X 3y = 'y' litres So, 3y + y = 96 Or, 4y = 96 Or, 'y' = 24 Initial quantity of water = 3 X 24 = 72 litres Initial quantity of milk = 24 litres Let quantity of milk require be 'a' litres. Resultant quantity of mixture = (96 + a) litres So, [72 ÷ (96 + a) ] X 100 = 40 Or, 96 + a = 180 Or, 'a' = 84
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