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Let the volumes of M, N, and O be 5x, 4x, and 3x liters respectively. Total volume = 5x + 4x + 3x = 12x liters Sugar in M = 5x × 0.60 = 3.00x liters Sugar in N = 4x × 0.50 = 2.00x liters Sugar in O = 3x × 0.40 = 1.20x liters Total sugar = 3.00x + 2.00x + 1.20x = 6.20x liters Percentage of sugar = (6.20x / 12x) × 100 = 51.67% The percentage of sugar in the mixture is approximately 52%. Correct Option: b
If (sinθ+cosθ)/(sinθ-cosθ) = 2, then the value of sin4 θ is
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