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Let total quantity of the mixture be x litres.
P = 4x/5 & Q = 1x/5
When 10 litres is removed (in 4:1 ratio), we remove:
P = 8 litres & Q = 2 litres
So remaining: P = (4x/5) −8 & Q = (1x/5) − 2
Then, 10 litres of Q is added:
New Q = 1x/5 – 2 + 10 = 1x/5 + 8
Now, new ratio is: P/Q = 2/3
So: {4x/5 – 8}/{1x/5 + 8} = 2/3
x = 20
So total mixture = 20 litres.
Amount of P = 4/5 × 20 = 16 litres
62 + 43 + 625(1/4) - ? = 102
(1/5)(40% of 800 – 120) = ? × 5
(21% of 360) ÷ 0.8 =?
1440 ÷ 12 + 540 ÷ √36 + ? = 180 * 3
Evaluate:
√729 + √49 - √16 + 1/√64
(2500 ÷ √625) × √(42.25) = ? ÷ 4
641.5 + 72 × 8 = ? × 4
1/6+ 999*53/54 ×9 = ?
24% of 75 + 36% of 100 = ?% of 180
{5% of (20 × 25) + 6% of (30 ×35)} ÷ 11 = ?