If a = 12, b = 23, c = 34, ............... z = 2627. How many zeros are formed after multiply a × b × c × ........... × z?
In this series, number of 2’s are very large & number of 5’s are very less so determine the number of zeros , we have to calculate number of 5’s only because these are less. 12 × 23 × 34 ×..............2627 56 = 6 1011 = 11 1516 = 16 2021 = 21 2526 = 5(2 x 26)= 52 ∴ Total number of zeroes = 6 + 11 + 16 + 21 + 52 = 106
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