Sum of two digits of a two digit number is 11. When digits of the number are reversed then number formed is 45 more than the original number. Find the original number.
Let the number be 10x + y. ATQ, => 10y + x – 10x - y = 45 => y – x = 5 ------ (i) => x + y = 11 ------ (ii) Solving (i) and (ii) , we get => x = 3 and y = 8 Therefore number = 38
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