If the 5-digit number 535ab is divisible by 3, 7 and 11, then what is the value of (a²-b² + ab)?
We have to find the number near 500, of the multiple of (7 × 11) = 77 Which is 539 and it should be the difference of pair of (3 digit) of given number 053 5ab = 5ab – 053 = 539 A = 9, b = 2 = 81 – 4 + 18 = 77 + 18 = 95
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