In a group of three numbers first is double of second and half of third. The average of three numbers is 42. Find the difference between the first number and third number?
Let the first number be ‘x’ Second number = x/2 Third number = 2x According to the question, (x+x/2+2x)/3 = 42 (2x+x+4x)/6 = 42 7x = 42 × 6 x = 36 ∴ Required difference = 72 - 36 = 36
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