Find the median of 5, 6, 10, 7, 7, 8, 6, 5 and 12.
To find the median, first we have to arrange the given numbers in ascending order as follows: 5, 6, 10, 7, 7, 8, 6, 5 and 12 5, 5, 6, 6, 7, 7, 8, 10 and 12 Since, number of terms is odd i.e. 9 So, median = [(9 + 1)/2]th term = 5th term Therefore, the median = 7
LCM and HCF of two numbers are respectively 3 and 18. If one of them is 9, find the other number.
Two numbers are in the ratio 4:7. The product of their H.C.F. and L.C.M. is 5488. The sum of the numbers is:
What is the least number which when divided by 3, 15 & 18 leave a remainder 6 in each case & it is also divisible by 12?
What is the least number of square tiles required to pave the floor of a room 11 m 47 cm long and 6 m 82 cm broad?
Find the least number of four digits which is exactly divisible by 6, 24 and 32?
Find the LCM of 25/14, 15/28, 30/21
The HCF of two numbers is 12. Which one of the following can never be their LCM?
Let x be the smallest number which when subtracted from 31560 makes the resulting number divisible by 13, 16, 25 and 30. The product of the digits of x ...
The sum of two numbers is 126 and their HCF is 14. Total number of such pairs of numbers is?