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The number C is 12.5% more than the number E. Let’s assume the number E is ‘8z’. Number C = (100+12.5)% of 8z = 112.5% of 8z = 9z The number C is 50% more than the number D. 9z = (100+50)% of the number D 9z = 150% of the number D number D = 9z/1.5 = 6z The average of the number B and C is 38. (number B + number C)/2 = 38 (number B + number C) = 76 (number B + 9z) = 76 number B = (76-9z) The number A is five less than the number B. number A = (number B - 5) = (76-9z)-5 = (71-9z) If the number D is 8 less than the number E. 6z = 8z-8 8z-6z = 8 2z = 8 z = 4 The ratio between the numbers of B and D is (y+1) : 3 respectively. (76-9z)/6z = (y+1)/3 Put the value of ‘z’ in the above equation. (76-9x4)/(6x4) = (y+1)/3 (76-36)/(2x4) = (y+1)/1 40/8 = (y+1)/1 (y+1) = 5 Value of ‘y’ = 5-1 = 4
6 7 15 46 185 ?
...D irection: Which of the following will replace ‘?’ in the following series.
543,’?’, 564 ,588, 660
...If 7 16 x 90 171 292
Then, 2x 2 + 1 + x ...
Three series are given below. You have to find the values of P, Q and R, then establish a relationship among them.
I: 210, P , 233, 64...
A’ is the nth term of the given series and ‘B’ is the (n + 1)th term of the given
series. Choose the correct statement from the following s...
? + (55)2= (140)2– (80)2– 6278
2 4 5 19 70...
5 6.5 20 113.5 799 ...
20, 30, 40, 55, ?, 160
There are three series given below which are following with the same pattern.
Series I: 9, 10, 32, 163, 1145
Series II: 4, B, C, D, E
...