How many 3-digit numbers are completely divisible by 5?
The first 3 digit that is completely divisible by 5 is 100. The last 3-digit number completely divisible by 5 is 995. Tn= a+ (n − 1) d ⇒ 995 = 100 + (n − 1)5 ⇒ (n − 1) = 895/5 = 179 ⇒ n = 180
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