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    Question

    A five digit number 2A78B, is divisible by 55. What is

    the difference between the maximum and minimum possible value of (A+B)?
    A 1 Correct Answer Incorrect Answer
    B 5 Correct Answer Incorrect Answer
    C 10 Correct Answer Incorrect Answer

    Solution

    Solution.

    2A78B

    2A78B is divisible by 55 Or 11×5.

    So, divisibility rule of 11 and 5

    a given number can only be completely divided by 11 if the difference of the sum of digits at odd position and sum of digits at even position in a number is 0 or 11 .

    If the last number is either 0 or 5, the entire number is divisible by 5 . 

    Maximum possible value of A and B=6 and 5

    Maximum possible value of A+B=6+5=11

    Minimum value of A and B=1 and 0

    Minimum value of (A+B) =1+0=1

    Difference between the maximum and minimum possible value of (A+B)=11-1=10.

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