Divide 54 into 4 parts such that if the first is increased by 2, the second is decreased by 2, the third is multiplied by 2 and the fourth divided by 2, the result is the same. Find out First part?
Let I, II, III, IV part are A, B, C, D respectively. Then A + B + C + D = 54 According to the question, ABCD x+2x-22xx/2 2x+4+2x-4+4x+x=54×2 9x =108 X=12. So, first number =12+2=14
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