Which term of the arithmetic progression 88, 90, 92, 94... is 142?
Given; 88, 90, 92, 94... T = 142 a=88 d=2 Tn=a+(n-1)-d 142=88+(n-1)-2 54=2n-2 56 = 2n n=28 Hence that post is the 28th.
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