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    Question

    The sum of the first 123 terms of the geometric

    progression (GP) is equal to the sum of the first 121 terms of the Ursa geometric progression (GP). When the first term is 1235, what is the 99th term in the same quality series?
    A 1435 Correct Answer Incorrect Answer
    B 1335 Correct Answer Incorrect Answer
    C 1235 Correct Answer Incorrect Answer
    D 1135 Correct Answer Incorrect Answer

    Solution

    S123= S121 a(r123-1)/r-1= a(r121-1)/r-1 r123 = r121 × 1 r2=1 r = ± 1 (all intervals) According to the question, r-1 First term = 1235 99th term of the series – T99 = a × r 99-1 = 1235 × 198 = 1235

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