Question
One-fifth of the attendees at an international banquet
were French men. If the number of French women at the banquet was 2/3 more than the number of French men and no other French citizens were present at the banquet, what was the share of non-French people at the banquet? type-sscSolution
In the international banquet- French guy=1/5 French women=2/3×1/5 +1/5 =2/15+1/5 =5/15 Remaining non-French=1-(1/5+5/15) =1-8/15 =7/15.
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I. 2x2 + 5x + 2 = 0
II. 4y2 = 1
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Equation 2: 31y² - 146y + ...
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I. 99 x² + 31 x – 110 = 0
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Equation 1: x² - 200x + 9600 = 0
Equation 2: y² - 190y + 9025 = 0
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Equation 2: y² - 51y + 630 = 0