Find the largest three-digit number that leaves '3', '4' and '5' as remainder when it is divided by '7', '8' and '9', respectively.
LCM (7, 8 and 9) = 504 We can see that in all three cases the remainder is 4 less than the number. So, required number = 504 - 4 = 500
40 42 87 266 ? 5366
22, 23, 31, 57, 122, 247
32, 65 , 196, 785, ? , 23557
19.11 × 5.98 + 20.03 × 3.12 – 34.95 + 97.9 × 3.02 =?
7200 7200 3600 1200 300 ?
...0.5 1.5 5 ? 76 385
...24, 33, 50, ?, 108, 149
25, 200, 40, ?, 64, 512
1400 350 700 175 ? 87.5
...7 12 33 ? 635 3804
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