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We know that a number is divisible by '3' only and when the sum of its digits is also divisible by 3 So, 1 + 7 + 6 + x + 9 + 5 = (28 + x) should be divisible by '3' So, possible values of 'x' = 2, 5, and 8 Or, maximum possible value of 'x' = 8 So, required value = 5 X 8 = 40
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