If y = ∛ 6 – 4, then what is the value of y³ + 12y² + 48y + 100?
y = ∛ 6 – 4 y + 4 = ∛ 6 (y + 4)3 = 6 y³ + 12y² + 48y + 64 = 6 y³ + 12y² + 48y +64 + 36 = 6 + 36 y³ + 12y² + 48y + 100 = 42 The value of y³ + 12y² + 48y +100 is 42.
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