In a certain pond, there are 60 more crabs than fish. Unfortunately, 20% of the crabs have perished. Additionally, the pond has welcomed 80 new fish. As a result, the current ratio of crabs to fish is 3:4. Determine the original quantities of crabs and fish in the pond.
Let the initial number of crabs in the pond be ‘x’ Therefore, initial number of fish in the pond = (x – 60) According to the question, 0.8x/(x – 60 + 80) = 3/4 Or, 3.2x – 3x = 60 Or, x = 60/0.2 = 300 Therefore, initial number of fish and crabs in the pond = (x + x – 60) = 540
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