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Given,
Set x = √(5a+9 and y = √(5a-9,
Giving x+y = 3(2+√2)
Square both sides, we get = (x+y)2 = 54+36√2.
By using x2 + y2 = 10a
On solving for 10a = 54,
So, 10a+9 = 63
Hence, √(10a+9) = √63 = 3√7
385! In the trailing Zeros, let us know.
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