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    Question

    The product of two positive

    integers is 121 times the product of one integer and the reciprocal of the other. If the sum of these two integers is 28, find the square of the larger integer.
    A 389 Correct Answer Incorrect Answer
    B 289 Correct Answer Incorrect Answer
    C 189 Correct Answer Incorrect Answer
    D 279 Correct Answer Incorrect Answer

    Solution

    ATQ, Let the two integers be ‘x’ and ‘y’ where x > y. Then, according to the question, x × y = x × (1/y) × 121 Or, xy = (121x/y) Or, 121x = xy2 So, y = √121 = 11 {since, ‘x’ and ‘y’ are positive integers} So, x = 28 – 11 = 17 Therefore, x2 = 172 = 289

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