Co-prime numbers are the ones whose HCF is 1. The possible number of pairs of ‘A’ and ‘B’, such that, ‘A’ and ‘B’ are co-prime = 2k – 1 Where, ‘k’ is the number of prime factors of the product. 350 = 21 × 52 × 71 So, the number of prime factors of 350 = k = 3 So, the possible number of pairs of ‘A’ and ‘B’, such that they are co-prime = 23 – 1 = 22 = 4
A six-digit number 23p7q6 is divisible by 24. Then the greatest possible value for (p + q) is:
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The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
What will be the remainder when 742 is divided by 48?
How many divisors does the number 5040 have?
A number n when divided by 6, leaves a remainder of 3. What will be the remainder when (n² +5n+8) is divided by 6?
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What will be the remainder when 577 + 87 is divided by 13?
which of the following pairs of non-zeroes values of p and q make the 6-digit number 674pq0 divisible by both 3 and 11?
A six-digit number 11p9q4 is divisible by 24. Then the greatest possible value for (p + q) is