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    Question

    Three numbers are in the ratio 5:9:12. The sum of the

    largest and smallest of these numbers is 8500. What is the difference between the largest and smallest numbers?
    A 3250 Correct Answer Incorrect Answer
    B 4200 Correct Answer Incorrect Answer
    C 3500 Correct Answer Incorrect Answer
    D 3320 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the smallest number be '5n'. So, the largest number = 5n  X (12/5) = 12n ATQ, 5n + 12n  = 8500 Or, 17n = 8500 So, 'n' = 500 Now, required difference = 12n - 5n = 7n = 7 × 500 = 3500

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