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ATQ, Let the tens and unit digit of the number be 2n and n respectively. According to the question: 2n + n = 12 n = 4 Number = 84 = 1 × 2 2 × 3 × 7 Number obtained after revering its digits = 48 = 1 × 24 * 3 HCF of 84 and 48 = 2 2 × 3 = 12
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