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Let, the two numbers be 'a' and 'b', such that, a > b.
ATQ,
a2 + b2 = 250
a - b = 4
(a - b) 2 = a2 + b2 + 2 X a X b
Or, 42 = 250 + 2 X a X b
Or, 2 X a X b = 250 - 16 = 234
Or, a X b = 117
a3 - b3 = (a - b) X (a2 + b2 + ab)
Or, a3 - b3 = 4 X (250 + 117) = 4 X 367 = 1,468
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