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    Question

    Sum of seven consecutive natural numbers is always

    divisible by which of the following number?
    A Cannot be determined Correct Answer Incorrect Answer
    B 3 Correct Answer Incorrect Answer
    C 9 Correct Answer Incorrect Answer
    D 7 Correct Answer Incorrect Answer

    Solution

    Let the numbers are 'n', 'n + 1', 'n + 2', 'n + 3', 'n + 4', 'n + 5' and 'n + 6'.

    Required sum = n + (n + 1) + (n + 2) + (n + 3) + (n + 4) + (n + 5) + (n + 6)
    = (7n + 21)

    = 7(n + 3)

    So, the sum is always divisible by 7.

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