Question
The digits of a two-digit number βNβ are reversed to
form a new number βMβ. If M < N and N β M = 45, then which of the following maybe βNβ?Solution
ATQ; Let the original number = N = β10a + bβ So, the new number = M = β10b + aβ ATQ; N = M + 45 So, 10a + b = 10b β a + 45 Or, 9a β 9b = 45 Or, a β b = 5 So, possible pairs of βaβ and βbβ = (9, 4), (8, 3), (7, 2), (6, 1) So, possible values of βNβ = 94, 83, 72, 61 Alternate Solution From option βaβ: N = 49 So, M = 94 Since, M > N {not possible} N = 61 So, M = 16 Also, N β M = 61 β 16 = 45
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I. ...
