Question

    ‘N’ be the highest 3-digit number which leaves a

    remainder of 3 when divided by 4, 6, and 9. What is the least number that must be added to ‘N’ to make it a perfect square?
    A 49 Correct Answer Incorrect Answer
    B 71 Correct Answer Incorrect Answer
    C 25 Correct Answer Incorrect Answer
    D 55 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM (4, 6, 9) = 36

    Highest 3-digit number divisible by 36 = 36 × 27 = 972

    So, N = 972 + 3 = 975

    Next perfect square after 975 is 32² = 1024

    Required number = 1024 - 975 = 49

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