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ATQ,
Let the first number be 'x'
Therefore, the five consecutive multiples of 3 will be 'x', (x + 3), (x + 6), (x + 9), (x + 12)
ATQ:
x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 5 × 24
Or, 5x + 30 = 120
Or, 5x = 120 - 30
Or, 5x = 90
Or, x = 90 ÷ 5 = 18
Therefore, the first number = 18
So, the smallest number is = 18
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