Get Started with ixamBee
Start learning 50% faster. Sign in now
Factors of 5 are 60, 65, 70, 75 and 80 so number of 5 = 6 and number of 2 is very high because every number is followed by even number. Hence, number of zeros = number of 10s = 5 and pair of 2s = 6 Alternate Method : Product = 60 × 61 × 62 × ........ × 80. So we can find number of zeroes in 80! then we can subtract number of zeroes in 59! . So 80/5 = 16 and 16/5 = 3 and adding all quoitent, number of zeroes = 16+3= 19; 59/5 = 11 and 11/5 =2, so number of zeroes in 59! = 11 + 2 = 13. So number of zeroes in the given product = 60 × 61 × 62 × ........ × 80? = 19 - 13 = 6.
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the question...
4 8 12 48 ? 432
...5 14 56 220 1125 6786
...3601 3602 1803 604 154 36
...? 12 24 44 74 116
...18 434 642 746 798 ?
...If 6 4 x 5.75 9,
Then, (x²-1) = ?
...2, A, 9, B, 6, C, 13, D, ?
1 5 36 343 ? 59049
...12, 16, 25, 41, 66, ?
