Divide 45 into 4 parts such that if the first is increased by 2, the second is decrease by 2, the third is multiplied by 2 and the fourth divided by 2, the result is the same. Find out First part?
Let I, II, III, and IV parts be A, B, C, and D respectively. Then A + B + C + D = 45 According to the question, ABCD x+2x-22xx/2 2x+4+2x-4+4x+x=45×2 9x =90 X=10. So first number =10+2=12
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