Question
The remainder obtained when (47³ + 35³) is divided by
41 isÂSolution
(an + bn) is always divisible by (a + b), when n is an odd power (47+35) = 82 Factors of 82 = (1, 2, 41 and 82) So, (47³ + 35³) is completely divided by 41 Hence, remainder = 0Â
Urea contains:Â
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