ATQ, Sum was to be divided in the ratio 3:4:5:8 Let the sum of A,B,C and D is 3x,4x,5x and 8x respectively According to question, we get 20x = 4360 x=218 so we get A = 654 ; B = 872 ; C = 1090; D =1744 But by mistake it was divided in the ratio; 1/3 : 1/4 : 1/5 : 1/8 By Equating , the ratio will be ; 40 : 34 : 24 : 15 New sum of A, B, C and D will be 40x, 30x, 24x and 15x respectively Solving in the same way, we get A = 1600 , B = 1200, C = 960 and D = 600 So we can say D got 1144 less
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