ATQ; {(3x × 9) + (3x + 500) × 3}/{(2x × 9) + (2x + 500) × 3} = 29/21 (27x + 9x + 1500) ÷ (18x + 6x + 1500) = (29/21) Or, (36x + 1500)/(24x + 1500) = 29/21 Or, 63x + 2625 = 58x + 3625 Or, 5x = 1000 Or, x = 200 Therefore, required difference = (3 × 200) – (2 × 200) = Rs. 200
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