‘M’, ‘N’, and ‘O’ initiated a partnership

Statements: G@B; W#Z; B%W

Conclusions:

I) G@Z

II) Z@B

Statements:

X = P < M = T > K; S > L ≥ M > O

Conclusions:

I).  T > O

II).  S > X

Statements: B & C, C # D, D @ E, E % F

Conclusions: I.    C & F                     II. E # B

Statements: T = S, U ≤ V, P < K, U ≤ K, V > S

Conclusion:

I. S ≥ U

II. S < U

Statements: E ≤ F = G ≤ H = I, M < L ≤ G = K ≥ J

Conclusion:

I. I ≤ L

II. I > M

III. E ≥ J 

Statement: I ≤ S, S < X, X = F, F ≤ K

Conclusion: I. K > I II. I < X

Statement: Y < Z > I < Q > S = M ≤ N

Conclusions:

I. S= N

II. Q > M

Statements: M = R ≥ S , N = O > Q, Q > W = A < S

Conclusions :I. N ≥ S

II. W > R

III. O ≤ S

Statements: F @ R, R $ J, V % J, V # Z

Statements: K ≥ N = I ≥ H ≤ U; B = S ≤ I

Conclusion: I. B < K II. B = K