ATQ, Let the incomes of ‘X’, ‘Y’, and ‘Z’ be Rs. x, Rs. y, and Rs. z. According to the question, 0.15x : 0.2y : 0.25z = 4 : 5 : 6 Or, x : y : z = (4/0.15) : (5/0.2) : (6/0.25) = 26.67 : 25 : 24 Sum of the ratios = 26.67 + 25 + 24 = 75.67 Therefore, income of ‘X’ = 21000 × (26.67/75.67) = Rs. 7435 Income of ‘Y’ = 21000 × (25/75.67) = Rs. 6966 Income of ‘Z’ = 21000 - (7435 + 6966) = Rs. 6599 Required sum = (0.85 × 7435) + (0.8 × 6966) + (0.75 × 6599) = 6320 + 5573 + 4949 = Rs.16842
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